# 0393. UTF-8 Validation

https://leetcode.com/problems/utf-8-validation

## Description

Given an integer array `data` representing the data, return whether it is a valid **UTF-8** encoding.

A character in **UTF8** can be from **1 to 4 bytes** long, subjected to the following rules:

1. For a **1-byte** character, the first bit is a `0`, followed by its Unicode code.
2. For an **n-bytes** character, the first `n` bits are all one's, the `n + 1` bit is `0`, followed by `n - 1` bytes with the most significant `2` bits being `10`.

This is how the UTF-8 encoding would work:

```
   Char. number range  |        UTF-8 octet sequence
      (hexadecimal)    |              (binary)
   --------------------+---------------------------------------------
   0000 0000-0000 007F | 0xxxxxxx
   0000 0080-0000 07FF | 110xxxxx 10xxxxxx
   0000 0800-0000 FFFF | 1110xxxx 10xxxxxx 10xxxxxx
   0001 0000-0010 FFFF | 11110xxx 10xxxxxx 10xxxxxx 10xxxxxx
```

**Note:** The input is an array of integers. Only the **least significant 8 bits** of each integer is used to store the data. This means each integer represents only 1 byte of data.

**Example 1:**

```
**Input:** data = [197,130,1]
**Output:** true
**Explanation:** data represents the octet sequence: 11000101 10000010 00000001.
It is a valid utf-8 encoding for a 2-bytes character followed by a 1-byte character.
```

**Example 2:**

```
**Input:** data = [235,140,4]
**Output:** false
**Explanation:** data represented the octet sequence: 11101011 10001100 00000100.
The first 3 bits are all one's and the 4th bit is 0 means it is a 3-bytes character.
The next byte is a continuation byte which starts with 10 and that's correct.
But the second continuation byte does not start with 10, so it is invalid.
```

**Constraints:**

* `1 <= data.length <= 2 * 104`
* `0 <= data[i] <= 255`

## ac

```java
```
