1046. Last Stone Weight
https://leetcode.com/problems/last-stone-weight
Description
You are given an array of integers stones
where stones[i]
is the weight of the ith
stone.
We are playing a game with the stones. On each turn, we choose the heaviest two stones and smash them together. Suppose the heaviest two stones have weights x
and y
with x <= y
. The result of this smash is:
If
x == y
, both stones are destroyed, andIf
x != y
, the stone of weightx
is destroyed, and the stone of weighty
has new weighty - x
.
At the end of the game, there is at most one stone left.
Return the smallest possible weight of the left stone. If there are no stones left, return 0
.
Example 1:
**Input:** stones = [2,7,4,1,8,1]
**Output:** 1
**Explanation:**
We combine 7 and 8 to get 1 so the array converts to [2,4,1,1,1] then,
we combine 2 and 4 to get 2 so the array converts to [2,1,1,1] then,
we combine 2 and 1 to get 1 so the array converts to [1,1,1] then,
we combine 1 and 1 to get 0 so the array converts to [1] then that's the value of the last stone.
Example 2:
**Input:** stones = [1]
**Output:** 1
Constraints:
1 <= stones.length <= 30
1 <= stones[i] <= 1000
ac
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