# 1577. Number of Ways Where Square of Number Is Equal to Product of Two Numbers

https://leetcode.com/problems/number-of-ways-where-square-of-number-is-equal-to-product-of-two-numbers

## Description

Given two arrays of integers `nums1` and `nums2`, return the number of triplets formed (type 1 and type 2) under the following rules:

* Type 1: Triplet (i, j, k) if `nums1[i]2 == nums2[j] * nums2[k]` where `0 <= i < nums1.length` and `0 <= j < k < nums2.length`.
* Type 2: Triplet (i, j, k) if `nums2[i]2 == nums1[j] * nums1[k]` where `0 <= i < nums2.length` and `0 <= j < k < nums1.length`.

**Example 1:**

```
**Input:** nums1 = [7,4], nums2 = [5,2,8,9]
**Output:** 1
**Explanation:** Type 1: (1,1,2), nums1[1]^2 = nums2[1] * nums2[2]. (4^2 = 2 * 8). 
```

**Example 2:**

```
**Input:** nums1 = [1,1], nums2 = [1,1,1]
**Output:** 9
**Explanation:** All Triplets are valid, because 1^2 = 1 * 1.
Type 1: (0,0,1), (0,0,2), (0,1,2), (1,0,1), (1,0,2), (1,1,2).  nums1[i]^2 = nums2[j] * nums2[k].
Type 2: (0,0,1), (1,0,1), (2,0,1). nums2[i]^2 = nums1[j] * nums1[k].
```

**Example 3:**

```
**Input:** nums1 = [7,7,8,3], nums2 = [1,2,9,7]
**Output:** 2
**Explanation:** There are 2 valid triplets.
Type 1: (3,0,2).  nums1[3]^2 = nums2[0] * nums2[2].
Type 2: (3,0,1).  nums2[3]^2 = nums1[0] * nums1[1].
```

**Example 4:**

```
**Input:** nums1 = [4,7,9,11,23], nums2 = [3,5,1024,12,18]
**Output:** 0
**Explanation:** There are no valid triplets.
```

**Constraints:**

* `1 <= nums1.length, nums2.length <= 1000`
* `1 <= nums1[i], nums2[i] <= 10^5`

## ac

```java
```
