# 1639. Number of Ways to Form a Target String Given a Dictionary

https://leetcode.com/problems/number-of-ways-to-form-a-target-string-given-a-dictionary

## Description

You are given a list of strings of the **same length** `words` and a string `target`.

Your task is to form `target` using the given `words` under the following rules:

* `target` should be formed from left to right.
* To form the `ith` character (**0-indexed**) of `target`, you can choose the `kth` character of the `jth` string in `words` if `target[i] = words[j][k]`.
* Once you use the `kth` character of the `jth` string of `words`, you **can no longer** use the `xth` character of any string in `words` where `x <= k`. In other words, all characters to the left of or at index `k` become unusuable for every string.
* Repeat the process until you form the string `target`.

**Notice** that you can use **multiple characters** from the **same string** in `words` provided the conditions above are met.

Return _the number of ways to form `target` from `words`_. Since the answer may be too large, return it **modulo** `109 + 7`.

**Example 1:**

```
**Input:** words = ["acca","bbbb","caca"], target = "aba"
**Output:** 6
**Explanation:** There are 6 ways to form target.
"aba" -> index 0 ("acca"), index 1 ("bbbb"), index 3 ("caca")
"aba" -> index 0 ("acca"), index 2 ("bbbb"), index 3 ("caca")
"aba" -> index 0 ("acca"), index 1 ("bbbb"), index 3 ("acca")
"aba" -> index 0 ("acca"), index 2 ("bbbb"), index 3 ("acca")
"aba" -> index 1 ("caca"), index 2 ("bbbb"), index 3 ("acca")
"aba" -> index 1 ("caca"), index 2 ("bbbb"), index 3 ("caca")
```

**Example 2:**

```
**Input:** words = ["abba","baab"], target = "bab"
**Output:** 4
**Explanation:** There are 4 ways to form target.
"bab" -> index 0 ("baab"), index 1 ("baab"), index 2 ("abba")
"bab" -> index 0 ("baab"), index 1 ("baab"), index 3 ("baab")
"bab" -> index 0 ("baab"), index 2 ("baab"), index 3 ("baab")
"bab" -> index 1 ("abba"), index 2 ("baab"), index 3 ("baab")
```

**Example 3:**

```
**Input:** words = ["abcd"], target = "abcd"
**Output:** 1
```

**Example 4:**

```
**Input:** words = ["abab","baba","abba","baab"], target = "abba"
**Output:** 16
```

**Constraints:**

* `1 <= words.length <= 1000`
* `1 <= words[i].length <= 1000`
* All strings in `words` have the same length.
* `1 <= target.length <= 1000`
* `words[i]` and `target` contain only lowercase English letters.

## ac

```java
```
