# 1807. Evaluate the Bracket Pairs of a String

https://leetcode.com/problems/evaluate-the-bracket-pairs-of-a-string

## Description

You are given a string `s` that contains some bracket pairs, with each pair containing a **non-empty** key.

* For example, in the string `"(name)is(age)yearsold"`, there are **two** bracket pairs that contain the keys `"name"` and `"age"`.

You know the values of a wide range of keys. This is represented by a 2D string array `knowledge` where each `knowledge[i] = [keyi, valuei]` indicates that key `keyi` has a value of `valuei`.

You are tasked to evaluate **all** of the bracket pairs. When you evaluate a bracket pair that contains some key `keyi`, you will:

* Replace `keyi` and the bracket pair with the key's corresponding `valuei`.
* If you do not know the value of the key, you will replace `keyi` and the bracket pair with a question mark `"?"` (without the quotation marks).

Each key will appear at most once in your `knowledge`. There will not be any nested brackets in `s`.

Return _the resulting string after evaluating **all** of the bracket pairs._

**Example 1:**

```
**Input:** s = "(name)is(age)yearsold", knowledge = [["name","bob"],["age","two"]]
**Output:** "bobistwoyearsold"
**Explanation:**
The key "name" has a value of "bob", so replace "(name)" with "bob".
The key "age" has a value of "two", so replace "(age)" with "two".
```

**Example 2:**

```
**Input:** s = "hi(name)", knowledge = [["a","b"]]
**Output:** "hi?"
**Explanation:** As you do not know the value of the key "name", replace "(name)" with "?".
```

**Example 3:**

```
**Input:** s = "(a)(a)(a)aaa", knowledge = [["a","yes"]]
**Output:** "yesyesyesaaa"
**Explanation:** The same key can appear multiple times.
The key "a" has a value of "yes", so replace all occurrences of "(a)" with "yes".
Notice that the "a"s not in a bracket pair are not evaluated.
```

**Example 4:**

```
**Input:** s = "(a)(b)", knowledge = [["a","b"],["b","a"]]
**Output:** "ba"
```

**Constraints:**

* `1 <= s.length <= 105`
* `0 <= knowledge.length <= 105`
* `knowledge[i].length == 2`
* `1 <= keyi.length, valuei.length <= 10`
* `s` consists of lowercase English letters and round brackets `'('` and `')'`.
* Every open bracket `'('` in `s` will have a corresponding close bracket `')'`.
* The key in each bracket pair of `s` will be non-empty.
* There will not be any nested bracket pairs in `s`.
* `keyi` and `valuei` consist of lowercase English letters.
* Each `keyi` in `knowledge` is unique.

## ac

```java
```
