# 1910. Remove All Occurrences of a Substring

https://leetcode.com/problems/remove-all-occurrences-of-a-substring

## Description

Given two strings `s` and `part`, perform the following operation on `s` until **all** occurrences of the substring `part` are removed:

* Find the **leftmost** occurrence of the substring `part` and **remove** it from `s`.

Return `s` _after removing all occurrences of_ `part`.

A **substring** is a contiguous sequence of characters in a string.

**Example 1:**

```
**Input:** s = "daabcbaabcbc", part = "abc"
**Output:** "dab"
**Explanation**: The following operations are done:
- s = "da**abc**baabcbc", remove "abc" starting at index 2, so s = "dabaabcbc".
- s = "daba**abc**bc", remove "abc" starting at index 4, so s = "dababc".
- s = "dab**abc**", remove "abc" starting at index 3, so s = "dab".
Now s has no occurrences of "abc".
```

**Example 2:**

```
**Input:** s = "axxxxyyyyb", part = "xy"
**Output:** "ab"
**Explanation**: The following operations are done:
- s = "axxx**xy**yyyb", remove "xy" starting at index 4 so s = "axxxyyyb".
- s = "axx**xy**yyb", remove "xy" starting at index 3 so s = "axxyyb".
- s = "ax**xy**yb", remove "xy" starting at index 2 so s = "axyb".
- s = "a**xy**b", remove "xy" starting at index 1 so s = "ab".
Now s has no occurrences of "xy".
```

**Constraints:**

* `1 <= s.length <= 1000`
* `1 <= part.length <= 1000`
* `s`​​​​​​ and `part` consists of lowercase English letters.

## ac

```java
```
