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# 1937. Maximum Number of Points with Cost

<https://leetcode.com/problems/maximum-number-of-points-with-cost>

## Description

You are given an `m x n` integer matrix `points` (**0-indexed**). Starting with `0` points, you want to **maximize** the number of points you can get from the matrix.

To gain points, you must pick one cell in **each row**. Picking the cell at coordinates `(r, c)` will **add** `points[r][c]` to your score.

However, you will lose points if you pick a cell too far from the cell that you picked in the previous row. For every two adjacent rows `r` and `r + 1` (where `0 <= r < m - 1`), picking cells at coordinates `(r, c1)` and `(r + 1, c2)` will **subtract** `abs(c1 - c2)` from your score.

Return *the **maximum** number of points you can achieve*.

`abs(x)` is defined as:

* `x` for `x >= 0`.
* `-x` for `x < 0`.

**Example 1:**

![](https://assets.leetcode.com/uploads/2021/07/12/screenshot-2021-07-12-at-13-40-26-diagram-drawio-diagrams-net.png)

```
**Input:** points = [[1,2,3],[1,5,1],[3,1,1]]
**Output:** 9
**Explanation:**
The blue cells denote the optimal cells to pick, which have coordinates (0, 2), (1, 1), and (2, 0).
You add 3 + 5 + 3 = 11 to your score.
However, you must subtract abs(2 - 1) + abs(1 - 0) = 2 from your score.
Your final score is 11 - 2 = 9.
```

**Example 2:**

![](https://assets.leetcode.com/uploads/2021/07/12/screenshot-2021-07-12-at-13-42-14-diagram-drawio-diagrams-net.png)

```
**Input:** points = [[1,5],[2,3],[4,2]]
**Output:** 11
**Explanation:**
The blue cells denote the optimal cells to pick, which have coordinates (0, 1), (1, 1), and (2, 0).
You add 5 + 3 + 4 = 12 to your score.
However, you must subtract abs(1 - 1) + abs(1 - 0) = 1 from your score.
Your final score is 12 - 1 = 11.
```

**Constraints:**

* `m == points.length`
* `n == points[r].length`
* `1 <= m, n <= 105`
* `1 <= m * n <= 105`
* `0 <= points[r][c] <= 105`

## ac

```java
```