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# 2011. Final Value of Variable After Performing Operations

<https://leetcode.com/problems/final-value-of-variable-after-performing-operations>

## Description

There is a programming language with only **four** operations and **one** variable `X`:

* `++X` and `X++` **increments** the value of the variable `X` by `1`.
* `--X` and `X--` **decrements** the value of the variable `X` by `1`.

Initially, the value of `X` is `0`.

Given an array of strings `operations` containing a list of operations, return *the **final** value of* `X` *after performing all the operations*.

**Example 1:**

```
**Input:** operations = ["--X","X++","X++"]
**Output:** 1
**Explanation:** The operations are performed as follows:
Initially, X = 0.
--X: X is decremented by 1, X =  0 - 1 = -1.
X++: X is incremented by 1, X = -1 + 1 =  0.
X++: X is incremented by 1, X =  0 + 1 =  1.
```

**Example 2:**

```
**Input:** operations = ["++X","++X","X++"]
**Output:** 3
**Explanation:** The operations are performed as follows:
Initially, X = 0.
++X: X is incremented by 1, X = 0 + 1 = 1.
++X: X is incremented by 1, X = 1 + 1 = 2.
X++: X is incremented by 1, X = 2 + 1 = 3.
```

**Example 3:**

```
**Input:** operations = ["X++","++X","--X","X--"]
**Output:** 0
**Explanation:** The operations are performed as follows:
Initially, X = 0.
X++: X is incremented by 1, X = 0 + 1 = 1.
++X: X is incremented by 1, X = 1 + 1 = 2.
--X: X is decremented by 1, X = 2 - 1 = 1.
X--: X is decremented by 1, X = 1 - 1 = 0.
```

**Constraints:**

* `1 <= operations.length <= 100`
* `operations[i]` will be either `"++X"`, `"X++"`, `"--X"`, or `"X--"`.

## ac

```java
```