# 0890. Find and Replace Pattern

<https://leetcode.com/problems/find-and-replace-pattern>

## Description

Given a list of strings `words` and a string `pattern`, return *a list of* `words[i]` *that match* `pattern`. You may return the answer in **any order**.

A word matches the pattern if there exists a permutation of letters `p` so that after replacing every letter `x` in the pattern with `p(x)`, we get the desired word.

Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.

**Example 1:**

```
**Input:** words = ["abc","deq","mee","aqq","dkd","ccc"], pattern = "abb"
**Output:** ["mee","aqq"]
**Explanation:** "mee" matches the pattern because there is a permutation {a -> m, b -> e, ...}. 
"ccc" does not match the pattern because {a -> c, b -> c, ...} is not a permutation, since a and b map to the same letter.
```

**Example 2:**

```
**Input:** words = ["a","b","c"], pattern = "a"
**Output:** ["a","b","c"]
```

**Constraints:**

* `1 <= pattern.length <= 20`
* `1 <= words.length <= 50`
* `words[i].length == pattern.length`
* `pattern` and `words[i]` are lowercase English letters.

## ac

```java
```
