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# 1150. Check If a Number Is Majority Element in a Sorted Array

<https://leetcode.com/problems/check-if-a-number-is-majority-element-in-a-sorted-array>

## Description

Given an integer array `nums` sorted in non-decreasing order and an integer `target`, return `true` *if* `target` *is a **majority** element, or* `false` *otherwise*.

A **majority** element in an array `nums` is an element that appears more than `nums.length / 2` times in the array.

**Example 1:**

```
**Input:** nums = [2,4,5,5,5,5,5,6,6], target = 5
**Output:** true
**Explanation:** The value 5 appears 5 times and the length of the array is 9.
Thus, 5 is a majority element because 5 > 9/2 is true.
```

**Example 2:**

```
**Input:** nums = [10,100,101,101], target = 101
**Output:** false
**Explanation:** The value 101 appears 2 times and the length of the array is 4.
Thus, 101 is not a majority element because 2 > 4/2 is false.
```

**Constraints:**

* `1 <= nums.length <= 1000`
* `1 <= nums[i], target <= 109`
* `nums` is sorted in non-decreasing order.

## ac

```java
```


---

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