> For the complete documentation index, see [llms.txt](https://jaywin.gitbook.io/leetcode/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://jaywin.gitbook.io/leetcode/solutions/1404-number-of-steps-to-reduce-a-number-in-binary-representation-to-one.md).

# 1404. Number of Steps to Reduce a Number in Binary Representation to One

<https://leetcode.com/problems/number-of-steps-to-reduce-a-number-in-binary-representation-to-one>

## Description

Given the binary representation of an integer as a string `s`, return *the number of steps to reduce it to* `1` *under the following rules*:

* If the current number is even, you have to divide it by `2`.
* If the current number is odd, you have to add `1` to it.

It is guaranteed that you can always reach one for all test cases.

**Example 1:**

```
**Input:** s = "1101"
**Output:** 6
**Explanation:** "1101" corressponds to number 13 in their decimal representation.
Step 1) 13 is odd, add 1 and obtain 14. 
Step 2) 14 is even, divide by 2 and obtain 7.
Step 3) 7 is odd, add 1 and obtain 8.
Step 4) 8 is even, divide by 2 and obtain 4.  
Step 5) 4 is even, divide by 2 and obtain 2. 
Step 6) 2 is even, divide by 2 and obtain 1.  
```

**Example 2:**

```
**Input:** s = "10"
**Output:** 1
**Explanation:** "10" corressponds to number 2 in their decimal representation.
Step 1) 2 is even, divide by 2 and obtain 1.  
```

**Example 3:**

```
**Input:** s = "1"
**Output:** 0
```

**Constraints:**

* `1 <= s.length <= 500`
* `s` consists of characters '0' or '1'
* `s[0] == '1'`

## ac

```java
```
