1829. Maximum XOR for Each Query

https://leetcode.com/problems/maximum-xor-for-each-query

Description

You are given a sorted array nums of n non-negative integers and an integer maximumBit. You want to perform the following query n times:

1. Find a non-negative integer k < 2maximumBit such that nums[0] XOR nums[1] XOR ... XOR nums[nums.length-1] XOR k is maximized. k is the answer to the ith query.

2. Remove the last element from the current array nums.

Return an array answer, where answer[i] is the answer to the ith query.

Example 1:

**Input:** nums = [0,1,1,3], maximumBit = 2
**Output:** [0,3,2,3]
**Explanation**: The queries are answered as follows:
1st query: nums = [0,1,1,3], k = 0 since 0 XOR 1 XOR 1 XOR 3 XOR 0 = 3.
2nd query: nums = [0,1,1], k = 3 since 0 XOR 1 XOR 1 XOR 3 = 3.
3rd query: nums = [0,1], k = 2 since 0 XOR 1 XOR 2 = 3.
4th query: nums = [0], k = 3 since 0 XOR 3 = 3.

Example 2:

**Input:** nums = [2,3,4,7], maximumBit = 3
**Output:** [5,2,6,5]
**Explanation**: The queries are answered as follows:
1st query: nums = [2,3,4,7], k = 5 since 2 XOR 3 XOR 4 XOR 7 XOR 5 = 7.
2nd query: nums = [2,3,4], k = 2 since 2 XOR 3 XOR 4 XOR 2 = 7.
3rd query: nums = [2,3], k = 6 since 2 XOR 3 XOR 6 = 7.
4th query: nums = [2], k = 5 since 2 XOR 5 = 7.

Example 3:

**Input:** nums = [0,1,2,2,5,7], maximumBit = 3
**Output:** [4,3,6,4,6,7]

Constraints:

• nums.length == n

• 1 <= n <= 105

• 1 <= maximumBit <= 20

• 0 <= nums[i] < 2maximumBit

• nums​​​ is sorted in ascending order.

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