# 0038. Count and Say

<https://leetcode.com/problems/count-and-say>

## Description

The **count-and-say** sequence is a sequence of digit strings defined by the recursive formula:

* `countAndSay(1) = "1"`
* `countAndSay(n)` is the way you would "say" the digit string from `countAndSay(n-1)`, which is then converted into a different digit string.

To determine how you "say" a digit string, split it into the **minimal** number of groups so that each group is a contiguous section all of the **same character.** Then for each group, say the number of characters, then say the character. To convert the saying into a digit string, replace the counts with a number and concatenate every saying.

For example, the saying and conversion for digit string `"3322251"`:

![](https://assets.leetcode.com/uploads/2020/10/23/countandsay.jpg) Given a positive integer `n`, return *the* `nth` *term of the **count-and-say** sequence*.

**Example 1:**

```
**Input:** n = 1
**Output:** "1"
**Explanation:** This is the base case.
```

**Example 2:**

```
**Input:** n = 4
**Output:** "1211"
**Explanation:**
countAndSay(1) = "1"
countAndSay(2) = say "1" = one 1 = "11"
countAndSay(3) = say "11" = two 1's = "21"
countAndSay(4) = say "21" = one 2 + one 1 = "12" + "11" = "1211"
```

**Constraints:**

* `1 <= n <= 30`

## ac

```java
class Solution {
    public String countAndSay(int n) {
        // edge cases
        if (n < 1) return "";

        //  generate
        String res = "1";
        for (int i = 1; i < n; i++) {
            res = counter(res);
        }

        return res;
    }
    private String counter(String s) {
        // input check
        if (s == null || s.length() < 1) return "";
        if (s.length() == 1) return "" + 1 + s;

        int cnt = 1;
        StringBuilder sb = new StringBuilder();
        for (int i = 1; i < s.length(); i++) {
            if (s.charAt(i) == s.charAt(i-1)) {
                cnt++;
            } else {
                sb.append(cnt);
                sb.append(s.charAt(i-1));
                cnt = 1;
            }
        }
            // final check
        sb.append(cnt);
        sb.append(s.charAt(s.length()-1));

        return sb.toString();
    }
}
```


---

# Agent Instructions: Querying This Documentation

If you need additional information that is not directly available in this page, you can query the documentation dynamically by asking a question.

Perform an HTTP GET request on the current page URL with the `ask` query parameter:

```
GET https://jaywin.gitbook.io/leetcode/solutions/0038-count-and-say.md?ask=<question>
```

The question should be specific, self-contained, and written in natural language.
The response will contain a direct answer to the question and relevant excerpts and sources from the documentation.

Use this mechanism when the answer is not explicitly present in the current page, you need clarification or additional context, or you want to retrieve related documentation sections.
