0281. Zigzag Iterator
https://leetcode.com/problems/zigzag-iterator
Description
Given two vectors of integers v1 and v2, implement an iterator to return their elements alternately.
Implement the ZigzagIterator class:
ZigzagIterator(List<int> v1, List<int> v2)initializes the object with the two vectorsv1andv2.boolean hasNext()returnstrueif the iterator still has elements, andfalseotherwise.int next()returns the current element of the iterator and moves the iterator to the next element.
Example 1:
**Input:** v1 = [1,2], v2 = [3,4,5,6]
**Output:** [1,3,2,4,5,6]
**Explanation:** By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,3,2,4,5,6].Example 2:
**Input:** v1 = [1], v2 = []
**Output:** [1]Example 3:
**Input:** v1 = [], v2 = [1]
**Output:** [1]Constraints:
0 <= v1.length, v2.length <= 10001 <= v1.length + v2.length <= 2000-231 <= v1[i], v2[i] <= 231 - 1
Follow up: What if you are given k vectors? How well can your code be extended to such cases?
Clarification for the follow-up question:
The "Zigzag" order is not clearly defined and is ambiguous for k > 2 cases. If "Zigzag" does not look right to you, replace "Zigzag" with "Cyclic".
Example:
**Input:** v1 = [1,2,3], v2 = [4,5,6,7], v3 = [8,9]
**Output:** [1,4,8,2,5,9,3,6,7]ac
public class ZigzagIterator {
private Queue<int[]> q;
private List<List<Integer>> lists;
public ZigzagIterator(List<Integer> v1, List<Integer> v2) {
lists = new ArrayList<List<Integer>>();
lists.add(v1);
lists.add(v2);
q = new LinkedList<int[]>();
if (v1.size() > 0) q.offer(new int[] {0, 0});
if (v2.size() > 0) q.offer(new int[] {1, 0});
}
public int next() {
int[] head = q.poll();
int res = lists.get(head[0]).get(head[1]);
if (++head[1] < lists.get(head[0]).size()) q.offer(head);
return res;
}
public boolean hasNext() {
return !q.isEmpty();
}
}
/**
* Your ZigzagIterator object will be instantiated and called as such:
* ZigzagIterator i = new ZigzagIterator(v1, v2);
* while (i.hasNext()) v[f()] = i.next();
*/Last updated
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