1101. The Earliest Moment When Everyone Become Friends
https://leetcode.com/problems/the-earliest-moment-when-everyone-become-friends
Description
There are n people in a social group labeled from 0 to n - 1. You are given an array logs where logs[i] = [timestampi, xi, yi] indicates that xi and yi will be friends at the time timestampi.
Friendship is symmetric. That means if a is friends with b, then b is friends with a. Also, person a is acquainted with a person b if a is friends with b, or a is a friend of someone acquainted with b.
Return the earliest time for which every person became acquainted with every other person. If there is no such earliest time, return -1.
Example 1:
**Input:** logs = [[20190101,0,1],[20190104,3,4],[20190107,2,3],[20190211,1,5],[20190224,2,4],[20190301,0,3],[20190312,1,2],[20190322,4,5]], n = 6
**Output:** 20190301
**Explanation:**
The first event occurs at timestamp = 20190101 and after 0 and 1 become friends we have the following friendship groups [0,1], [2], [3], [4], [5].
The second event occurs at timestamp = 20190104 and after 3 and 4 become friends we have the following friendship groups [0,1], [2], [3,4], [5].
The third event occurs at timestamp = 20190107 and after 2 and 3 become friends we have the following friendship groups [0,1], [2,3,4], [5].
The fourth event occurs at timestamp = 20190211 and after 1 and 5 become friends we have the following friendship groups [0,1,5], [2,3,4].
The fifth event occurs at timestamp = 20190224 and as 2 and 4 are already friends anything happens.
The sixth event occurs at timestamp = 20190301 and after 0 and 3 become friends we have that all become friends.Example 2:
**Input:** logs = [[0,2,0],[1,0,1],[3,0,3],[4,1,2],[7,3,1]], n = 4
**Output:** 3Constraints:
2 <= n <= 1001 <= logs.length <= 104logs[i].length == 30 <= timestampi <= 1090 <= xi, yi <= n - 1xi != yiAll the values
timestampiare unique.All the pairs
(xi, yi)occur at most one time in the input.
ac
Last updated
Was this helpful?