0901. Online Stock Span
https://leetcode.com/problems/online-stock-span
Description
Design an algorithm that collects daily price quotes for some stock and returns the span of that stock's price for the current day.
The span of the stock's price today is defined as the maximum number of consecutive days (starting from today and going backward) for which the stock price was less than or equal to today's price.
For example, if the price of a stock over the next
7
days were[100,80,60,70,60,75,85]
, then the stock spans would be[1,1,1,2,1,4,6]
.
Implement the StockSpanner
class:
StockSpanner()
Initializes the object of the class.int next(int price)
Returns the span of the stock's price given that today's price isprice
.
Example 1:
**Input**
["StockSpanner", "next", "next", "next", "next", "next", "next", "next"]
[[], [100], [80], [60], [70], [60], [75], [85]]
**Output**
[null, 1, 1, 1, 2, 1, 4, 6]
**Explanation**
StockSpanner stockSpanner = new StockSpanner();
stockSpanner.next(100); // return 1
stockSpanner.next(80); // return 1
stockSpanner.next(60); // return 1
stockSpanner.next(70); // return 2
stockSpanner.next(60); // return 1
stockSpanner.next(75); // return 4, because the last 4 prices (including today's price of 75) were less than or equal to today's price.
stockSpanner.next(85); // return 6
Constraints:
1 <= price <= 105
At most
104
calls will be made tonext
.
ac: Monotonic queue
Intuitive version:
class StockSpanner {
Deque<int[]> stack; // [day, price]
int day;
public StockSpanner() {
stack = new ArrayDeque<>();
day = 0;
}
public int next(int price) {
while (!stack.isEmpty() && stack.peek()[1] <= price) {
stack.pop();
}
int span = 1;
if (stack.isEmpty()) {
span = Math.max(span, day + 1);
} else {
int[] stock = stack.peek();
span = Math.max(span, day - stock[0]);
}
stack.push(new int[]{day, price});
day++;
return span;
}
}
/**
* Your StockSpanner object will be instantiated and called as such:
* StockSpanner obj = new StockSpanner();
* int param_1 = obj.next(price);
*/
This is more concise:
class StockSpanner {
Deque<int[]> stack; // [span, price]
public StockSpanner() {
stack = new ArrayDeque<>();
}
public int next(int price) {
int span = 1;
while (!stack.isEmpty() && stack.peek()[1] <= price) {
span += stack.pop()[0]; // Sum up span of previous smaller price.
}
stack.push(new int[]{span, price});
return span;
}
}
Last updated
Was this helpful?