# 1391. Check if There is a Valid Path in a Grid

<https://leetcode.com/problems/check-if-there-is-a-valid-path-in-a-grid>

## Description

Given a *m* x *n* `grid`. Each cell of the `grid` represents a street. The street of `grid[i][j]` can be:

* **1** which means a street connecting the left cell and the right cell.
* **2** which means a street connecting the upper cell and the lower cell.
* **3** which means a street connecting the left cell and the lower cell.
* **4** which means a street connecting the right cell and the lower cell.
* **5** which means a street connecting the left cell and the upper cell.
* **6** which means a street connecting the right cell and the upper cell.

![](https://assets.leetcode.com/uploads/2020/03/05/main.png)

You will initially start at the street of the upper-left cell `(0,0)`. A valid path in the grid is a path which starts from the upper left cell `(0,0)` and ends at the bottom-right cell `(m - 1, n - 1)`. **The path should only follow the streets**.

**Notice** that you are **not allowed** to change any street.

Return *true* if there is a valid path in the grid or *false* otherwise.

**Example 1:**

![](https://assets.leetcode.com/uploads/2020/03/05/e1.png)

```
**Input:** grid = [[2,4,3],[6,5,2]]
**Output:** true
**Explanation:** As shown you can start at cell (0, 0) and visit all the cells of the grid to reach (m - 1, n - 1).
```

**Example 2:**

![](https://assets.leetcode.com/uploads/2020/03/05/e2.png)

```
**Input:** grid = [[1,2,1],[1,2,1]]
**Output:** false
**Explanation:** As shown you the street at cell (0, 0) is not connected with any street of any other cell and you will get stuck at cell (0, 0)
```

**Example 3:**

```
**Input:** grid = [[1,1,2]]
**Output:** false
**Explanation:** You will get stuck at cell (0, 1) and you cannot reach cell (0, 2).
```

**Example 4:**

```
**Input:** grid = [[1,1,1,1,1,1,3]]
**Output:** true
```

**Example 5:**

```
**Input:** grid = [[2],[2],[2],[2],[2],[2],[6]]
**Output:** true
```

**Constraints:**

* `m == grid.length`
* `n == grid[i].length`
* `1 <= m, n <= 300`
* `1 <= grid[i][j] <= 6`

## ac

```java
```
