1387. Sort Integers by The Power Value
https://leetcode.com/problems/sort-integers-by-the-power-value
Description
The power of an integer x is defined as the number of steps needed to transform x into 1 using the following steps:
if
xis even thenx = x / 2if
xis odd thenx = 3 * x + 1
For example, the power of x = 3 is 7 because 3 needs 7 steps to become 1 (3 --> 10 --> 5 --> 16 --> 8 --> 4 --> 2 --> 1).
Given three integers lo, hi and k. The task is to sort all integers in the interval [lo, hi] by the power value in ascending order, if two or more integers have the same power value sort them by ascending order.
Return the k-th integer in the range [lo, hi] sorted by the power value.
Notice that for any integer x (lo <= x <= hi) it is guaranteed that x will transform into 1 using these steps and that the power of x is will fit in 32 bit signed integer.
Example 1:
**Input:** lo = 12, hi = 15, k = 2
**Output:** 13
**Explanation:** The power of 12 is 9 (12 --> 6 --> 3 --> 10 --> 5 --> 16 --> 8 --> 4 --> 2 --> 1)
The power of 13 is 9
The power of 14 is 17
The power of 15 is 17
The interval sorted by the power value [12,13,14,15]. For k = 2 answer is the second element which is 13.
Notice that 12 and 13 have the same power value and we sorted them in ascending order. Same for 14 and 15.Example 2:
**Input:** lo = 1, hi = 1, k = 1
**Output:** 1Example 3:
**Input:** lo = 7, hi = 11, k = 4
**Output:** 7
**Explanation:** The power array corresponding to the interval [7, 8, 9, 10, 11] is [16, 3, 19, 6, 14].
The interval sorted by power is [8, 10, 11, 7, 9].
The fourth number in the sorted array is 7.Example 4:
**Input:** lo = 10, hi = 20, k = 5
**Output:** 13Example 5:
**Input:** lo = 1, hi = 1000, k = 777
**Output:** 570Constraints:
1 <= lo <= hi <= 10001 <= k <= hi - lo + 1
ac
Last updated
Was this helpful?