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# 1335. Minimum Difficulty of a Job Schedule

<https://leetcode.com/problems/minimum-difficulty-of-a-job-schedule>

## Description

You want to schedule a list of jobs in `d` days. Jobs are dependent (i.e To work on the `i-th` job, you have to finish all the jobs `j` where `0 <= j < i`).

You have to finish **at least** one task every day. The difficulty of a job schedule is the sum of difficulties of each day of the `d` days. The difficulty of a day is the maximum difficulty of a job done in that day.

Given an array of integers `jobDifficulty` and an integer `d`. The difficulty of the `i-th` job is `jobDifficulty[i]`.

Return *the minimum difficulty* of a job schedule. If you cannot find a schedule for the jobs return **-1**.

**Example 1:**

![](https://assets.leetcode.com/uploads/2020/01/16/untitled.png)

```
**Input:** jobDifficulty = [6,5,4,3,2,1], d = 2
**Output:** 7
**Explanation:** First day you can finish the first 5 jobs, total difficulty = 6.
Second day you can finish the last job, total difficulty = 1.
The difficulty of the schedule = 6 + 1 = 7 
```

**Example 2:**

```
**Input:** jobDifficulty = [9,9,9], d = 4
**Output:** -1
**Explanation:** If you finish a job per day you will still have a free day. you cannot find a schedule for the given jobs.
```

**Example 3:**

```
**Input:** jobDifficulty = [1,1,1], d = 3
**Output:** 3
**Explanation:** The schedule is one job per day. total difficulty will be 3.
```

**Example 4:**

```
**Input:** jobDifficulty = [7,1,7,1,7,1], d = 3
**Output:** 15
```

**Example 5:**

```
**Input:** jobDifficulty = [11,111,22,222,33,333,44,444], d = 6
**Output:** 843
```

**Constraints:**

* `1 <= jobDifficulty.length <= 300`
* `0 <= jobDifficulty[i] <= 1000`
* `1 <= d <= 10`

## ac

```java
```