# 1433. Check If a String Can Break Another String

<https://leetcode.com/problems/check-if-a-string-can-break-another-string>

## Description

Given two strings: `s1` and `s2` with the same size, check if some permutation of string `s1` can break some permutation of string `s2` or vice-versa. In other words `s2` can break `s1` or vice-versa.

A string `x` can break string `y` (both of size `n`) if `x[i] >= y[i]` (in alphabetical order) for all `i` between `0` and `n-1`.

**Example 1:**

```
**Input:** s1 = "abc", s2 = "xya"
**Output:** true
**Explanation:** "ayx" is a permutation of s2="xya" which can break to string "abc" which is a permutation of s1="abc".
```

**Example 2:**

```
**Input:** s1 = "abe", s2 = "acd"
**Output:** false 
**Explanation:** All permutations for s1="abe" are: "abe", "aeb", "bae", "bea", "eab" and "eba" and all permutation for s2="acd" are: "acd", "adc", "cad", "cda", "dac" and "dca". However, there is not any permutation from s1 which can break some permutation from s2 and vice-versa.
```

**Example 3:**

```
**Input:** s1 = "leetcodee", s2 = "interview"
**Output:** true
```

**Constraints:**

* `s1.length == n`
* `s2.length == n`
* `1 <= n <= 10^5`
* All strings consist of lowercase English letters.

## ac

```java
```


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