1622. Fancy Sequence
https://leetcode.com/problems/fancy-sequence
Description
Write an API that generates fancy sequences using the append, addAll, and multAll operations.
Implement the Fancy class:
Fancy()Initializes the object with an empty sequence.void append(val)Appends an integervalto the end of the sequence.void addAll(inc)Increments all existing values in the sequence by an integerinc.void multAll(m)Multiplies all existing values in the sequence by an integerm.int getIndex(idx)Gets the current value at indexidx(0-indexed) of the sequence modulo109 + 7. If the index is greater or equal than the length of the sequence, return-1.
Example 1:
**Input**
["Fancy", "append", "addAll", "append", "multAll", "getIndex", "addAll", "append", "multAll", "getIndex", "getIndex", "getIndex"]
[[], [2], [3], [7], [2], [0], [3], [10], [2], [0], [1], [2]]
**Output**
[null, null, null, null, null, 10, null, null, null, 26, 34, 20]
**Explanation**
Fancy fancy = new Fancy();
fancy.append(2); // fancy sequence: [2]
fancy.addAll(3); // fancy sequence: [2+3] -> [5]
fancy.append(7); // fancy sequence: [5, 7]
fancy.multAll(2); // fancy sequence: [5*2, 7*2] -> [10, 14]
fancy.getIndex(0); // return 10
fancy.addAll(3); // fancy sequence: [10+3, 14+3] -> [13, 17]
fancy.append(10); // fancy sequence: [13, 17, 10]
fancy.multAll(2); // fancy sequence: [13*2, 17*2, 10*2] -> [26, 34, 20]
fancy.getIndex(0); // return 26
fancy.getIndex(1); // return 34
fancy.getIndex(2); // return 20Constraints:
1 <= val, inc, m <= 1000 <= idx <= 105At most
105calls total will be made toappend,addAll,multAll, andgetIndex.
ac
Last updated
Was this helpful?